## NURS8200 Week 4 Descriptive Statistics In Nursing Research Assignment

### Week 4 Descriptive Statistics

To Prepare:

Review the Statistics and Data Analysis for Nursing Research chapters assigned in this week’s Learning Resources. Pay close attention to the examples presented, as they provide information that will be useful when you complete the software exercise this week. You may also wish to review the Research Methods for Evidence-Based Practice video resources to familiarize yourself with the software.

Refer to the Week 4 Descriptive Statistics Assignment page and follow the directions to calculate descriptive statistics for the data provided using SPSS software. Download and save the Polit2SetA.sav data set. You will open the data file in SPSS.

Compare your data output against the tables presented in the Week 4 Descriptive Statistics SPSS Output document. This will enable you to become comfortable with defining variables, entering data, and creating tables and graphs.

Formulate an initial interpretation of the meaning or implication of your calculations.

To Complete:

- Complete the Part I, Part II, and Part III steps and Assignment as outlined in the Week 4 Descriptive Statistics Assignment page.

### Part I

Using the Polit2SetA data set, run descriptive statistics on the following variables: respondent’s age (age) and highest school grade completed (grade). Create a frequency distribution for the variables: race and ethnicity (race) and currently employed (worknow). Create a table (in APA format) summarizing the results, using the below table shell as a model. Write a paragraph summarizing the information in the table. Table 1.

- Demographic Data (N = 30)
- n % M (SD)
- Age (in years) 30 15(2.4)
- Highest School Grade Completed 29 11(1.2)
- Race and Ethnicity
- Black, Not Hispanic 14 (46.67)
- Hispanic 8 (26.67)
- White, Not Hispanic 6 (20.0)
- Other 2 (6.66)
- Currently Employed
- Yes 27 (90)
- No 3 (10)

Note. Differences in sample size are due to missing data.

Follow these steps when using SPSS:

- Open Polit2SetA data set.
- Click on Analyze, then click on Descriptives Statistics, then Descriptives.
- Click on the first continuous variable you wish to obtain descriptives for (respondent’s age), and then click on the arrow button and move it into the Variables box. Then click on the highest school grade completed and then click on the arrow button and move it into the Variables box.
- Click on the Options button in the upper-right corner. Click on mean, standard deviation, minimum, maximum, and skewness.
- Click on Continue and then click on OK.

To run the frequency distribution in SPSS, do the following:

- Click on Analyze, then click on Descriptive Statistics, then Frequencies.
- Click on the first categorical variable you wish to obtain a frequency for (race and ethnicity), and then click on the arrow button and move it into the Variables box. Then click on currently employed, and then click on the arrow button and move it into the Variables box. Click on the Statistics button in the upper-right corner, then in the Dispersion box click on Minimum and Maximum.
- Click on Continue and then click on OK.

Assignment: Create a table (in APA format) summarizing the results, using the below table shell as a model. Write a paragraph summarizing the information in the table.

### Part II

For the variables respondent’s age (age) and highest school grade completed (grade) create a histogram with a normal curve displayed over the histogram.

To create a histogram for respondent’s age in SPSS, do the following:

- Click on Graphs, then on Legacy Dialogs, then Histogram.
- Click on the variable respondent’s age and then click on the arrow button and move it into the Variables box. Click on the Display Normal Curve button, which is right below the Variables box.
- Click on OK.

To create a histogram for highest school grade completed in SPSS, do the following:

- Click on Graphs, then on Legacy Dialogs, then Histogram.
- Click on respondent’s age in the Variable box and click the arrow to move it back to the box on the left that contains all the variables.
- Click on the variable highest school grade completed and then click the arrow button and move it into the Variables box. The Display Normal Curve button should already be on.
- Click on OK.

Assignment: Using the data obtained when you ran the descriptives and the histograms, determine whether the data skewed. If so, is it a positive or negative skew?

### Part III

Using the Polit2SetA data set, run descriptive statistics on the variable “Family Income Prior Month, all sources” (Income).

Follow these steps when using SPSS:

- Click on Analyze, then click on Descriptives Statistics, then Descriptives.
- Click on Family Income Prior Month, all sources, and then click on the arrow button and move it into the Variables box.
- Click on the Options button in the upper-right corner. Click on mean, standard deviation, minimum, maximum, S.E. Mean (standard error of the mean), and skewness.
- Click on Continue and then click on OK.

Assignment: Using the descriptive statistics for Family Income Prior Month, all sources (Income), answer the following questions:

- What is the mean income in this sample?
- What is the standard deviation?
- What is the standard error of the mean?
- Compute a 95% confidence interval around the mean. (Use 1.96 for the 95% CI and get the standard error from the descriptive statistics table). The formula is as follows: 95% CI = [mean ± (1.96 ´ SE)]
- Compute a 99% confidence interval around the mean. (Use 2.58 for the 99% CI and get the standard error from the descriptive statistics table). The formula is as follows: 99% CI = [mean ± (2.58 ´ SE)]
- Which interval is wider? Explain.

Review the corresponding Week 4 Descriptive Statistics Exercises SPSS Output document that has the SPSS output for the above problems. Compare your output with the output in the file.

#### REFERENCES

- laureate Education, Inc. (Executive Producer). (2011). Research methods for evidence-based practice: Quantitative research: Data analysis. Baltimore, MD: Author.
- Polit, D. (2010). Statistics and data analysis for nursing research (2nd ed.). Upper Saddle River, NJ: Pearson Education Inc.
- Chapter 1, “Introduction to Data Analysis in an Evidence-Based Practice Environment”

### Week 4 Descriptive Statistics Exercises SPSS Output

#### Part I

Respondent’s Age Descriptive Statistics

N Minimum Maximum Mean Std. Deviation Skewness Statistic Statistic Statistic Statistic Statistic Statistic Std. Error Respondent’s age at time of interview

- 1000 19.378 49.430 36.63733 6.198741 -.374 .077
- Valid N (listwise) 1000
- Highest School Grade Completed
- Descriptive Statistics

N Minimum Maximum Mean Std. Deviation Skewness Statistic Statistic Statistic Statistic Statistic Statistic Std. Error Highest school grade completed

- 989 1 16 11.28 1.561 -.727 .078
- Valid N (listwise) 989
- Race and Ethnicity
- Race/ethnicity
- Frequency Percent Valid Percent
- Cumulative
- Percent
- Valid Black, not Hispanic 803 80.3 80.5 80.5
- Hispanic 128 12.8 12.8 93.3
- White, not Hispanic 53 5.3 5.3 98.6
- Other 14 1.4 1.4 100.0
- Total 998 99.8 100.0 Missing Refused 1 .1
- DK 1 .1 Total 2 .2
- Total 1000 100.0
- Currently Employed
- Currently employed?
- Frequency Percent Valid Percent
- Cumulative
- Percent
- Valid No 546 54.6 54.7 54.7
- Yes 452 45.2 45.3 100.0
- Total 998 99.8 100.0 Missing System 2 .2 Total 1000 100.0

#### Part II

#### Part III Family Income

Descriptive Statistics

- N Minimum Maximum Mean Std. Deviation Skewness Statistic
- Statistic Std. Error Statistic Statistic Std. Error Family income prior month, all sources
- 895 $0 $6,593 $1,172.59 $26.345 $788.153 2.030 .082
- Valid N (listwise) 895
- Statistics
- Respondent’s age at time of interview
- N Valid 1000
- Missing 0
- Mean 36.63733
- Median 37.36849
- Std. Deviation 6.198741
- Range 30.052
- Minimum 19.378
- Maximum 49.430
- DESCRIPTIVES VARIABLES=age high grade
- /STATISTICS=MEAN STDDEV MIN MAX SKEWNESS.

#### Descriptives

Descriptive Statistics

- N Minimum Maximum Mean Std. Deviation Skewness
- Statistic Statistic Statistic Statistic Statistic Statistic Std. Error
- Respondent’s age at time of interview 1000 19.378 49.430 36.63733 6.198741 -.374 .077
- Highest school grade completed 989 1 16 11.28 1.561 -.727 .078
- Valid N (listwise) 989
- Statistics
- Race/ethnicity Currently employed?
- N Valid 998 998
- Missing 2 2
- Minimum 1 0
- Maximum 4 1
- Frequency Table
- Race/ethnicity
- Frequency Percent Valid Percent Cumulative Percent
- Valid Black, not Hispanic 803 80.3 80.5 80.5
- Hispanic 128 12.8 12.8 93.3
- White, not Hispanic 53 5.3 5.3 98.6
- Other 14 1.4 1.4 100.0
- Total 998 99.8 100.0
- Missing Refused 1 .1
- DK 1 .1
- Total 2 .2 Total 1000 100.0
- Currently employed?
- Frequency Percent Valid Percent Cumulative Percent
- Valid No 546 54.6 54.7 54.7
- Yes 452 45.2 45.3 100.0
- Total 998 99.8 100.0
- Missing System 2 .2
- Total 1000 100.0

The study in this data set was conducted using women in low economic status communities (Polit, 2010). The data in each table represents an occurrence or a trait shared by the women in the group. The results show that women’s ages ranged from 19 to 49 years of age and had completed anywhere from 1 year of school to 16 years. The majority of women were black, followed by Hispanics, whites and others. Out of these women only one had refused to give information on her race or ethnicity. The majority of the women were not employed.

#### PART II

In the first histogram, the information is negatively skewed. The long tail is pointed to the left. This histogram shows the respondents ages. In the next histogram is symmetric and can be split down the middle to mirror each half.

#### Part III

Family Income

Descriptive Statistics

N Minimum Maximum Mean Std. Deviation Skewness

Statistic Statistic Statistic Statistic Std. Error Statistic Statistic Std. Error

Family income prior month, all sources 895 $0 $6,593 $1,172.59 $26.345 $788.153

2.030 .082

Valid N (listwise) 895

Questions

- What is the meaning of this sample?
- What is the standard deviation?
- What is the standard error of the mean?
- 95% CI =Mean(1,172.59$ +(-)(1.96x.$26.346)=
- 99%CI=(1,172.59$+(-)(2.58 x $26.346)=
- What interval is wider ? Explain

Answers

- $1,172.59
- $788.153
- $26.345
- 1,224.2262,1120.95184=103
- 1,240.56268, 1,104.61732=135
- The 99% interval is wider because it covers more possibilities and the likelihood of being correct is greater.

##### Resources

- Polit, D. (2010). Statistics and data analysis for nursing research (2nd ed.). Upper Saddle.